(x^2+9)-2(x-3)+1=0

Solution for (x^2+9)-2(x-3)+1=0 equation:

Simplifying
(x2 + 9) + -2(x + -3) + 1 = 0

Reorder the terms:
(9 + x2) + -2(x + -3) + 1 = 0

Remove parenthesis around (9 + x2)
9 + x2 + -2(x + -3) + 1 = 0

Reorder the terms:
9 + x2 + -2(-3 + x) + 1 = 0
9 + x2 + (-3 * -2 + x * -2) + 1 = 0
9 + x2 + (6 + -2x) + 1 = 0

Reorder the terms:
9 + 6 + 1 + -2x + x2 = 0

Combine like terms: 9 + 6 = 15
15 + 1 + -2x + x2 = 0

Combine like terms: 15 + 1 = 16
16 + -2x + x2 = 0

Solving
16 + -2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + -2x + -16 + x2 = 0 + -16

Reorder the terms:
16 + -16 + -2x + x2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -2x + x2 = 0 + -16
-2x + x2 = 0 + -16

Combine like terms: 0 + -16 = -16
-2x + x2 = -16

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -16 + 1

Reorder the terms:
1 + -2x + x2 = -16 + 1

Combine like terms: -16 + 1 = -15
1 + -2x + x2 = -15

Factor a perfect square on the left side:
(x + -1)(x + -1) = -15

Can't calculate square root of the right side.

The solution to this equation could not be determined.